Найти произведение чисел:
| \(\displaystyle 2\) | \(\displaystyle 2\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle 3\) | |||
| x | |||||||
| \(\displaystyle 2\) | \(\displaystyle 1\) | \(\displaystyle 2\) | |||||
| \(\displaystyle +\) | |||||||
| \(\displaystyle +\) | |||||||
1. Первое действие.
Умножаем единицы числа \(\displaystyle 21{\underline 2}\) (это число \(\displaystyle 2\)) на число \(\displaystyle 22123{\small:}\)
\(\displaystyle 22123 \cdot 2=44246\).
| \(\displaystyle 2\) | \(\displaystyle 2\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle 3\) | |||
| x | |||||||
| \(\displaystyle 2\) | \(\displaystyle 1\) | \(\displaystyle \bf2\) | |||||
| \(\displaystyle \bf4\) | \(\displaystyle \bf4\) | \(\displaystyle \bf2\) | \(\displaystyle \bf4\) | \(\displaystyle \bf6\) | |||
| \(\displaystyle +\) | |||||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |||
| \(\displaystyle +\) | |||||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |
2. Второе действие.
Умножаем десятки числа \(\displaystyle 2{\underline 1}2\) (это число \(\displaystyle 1\)) на число \(\displaystyle 22123{\small:}\)
\(\displaystyle 22123 \cdot 1=22123{\small.}\)
Записываем результат так, чтобы единицы \(\displaystyle 2212{\underline 3}\) шли под той цифрой, на которую мы умножали (в нашем случае это десятки числа \(\displaystyle 2{\underline1}2{\small,}\) то есть число \(\displaystyle 1\)).
| \(\displaystyle 2\) | \(\displaystyle 2\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle 3\) | |||
| x | |||||||
| \(\displaystyle 2\) | \(\displaystyle \bf1\) | \(\displaystyle 2\) | |||||
| \(\displaystyle 4\) | \(\displaystyle 4\) | \(\displaystyle 2\) | \(\displaystyle 4\) | \(\displaystyle 6\) | |||
| \(\displaystyle +\) | |||||||
| \(\displaystyle \bf2\) | \(\displaystyle \bf2\) | \(\displaystyle \bf1\) | \(\displaystyle \bf2\) | \(\displaystyle \bf3\) | |||
| \(\displaystyle +\) | |||||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |
3. Третье действие.
Умножаем сотни числа \(\displaystyle {\underline 2}12\) (это число \(\displaystyle 2\)) на число \(\displaystyle 22123{\small:}\)
\(\displaystyle 22123 \cdot 2=44246{\small.}\)
Записываем результат так, чтобы единицы \(\displaystyle 4424{\underline 6}\) шли под той цифрой, на которую мы умножали (в нашем случае это сотни числа \(\displaystyle {\underline 2}12{\small,}\) то есть число \(\displaystyle 2\)).
| \(\displaystyle 2\) | \(\displaystyle 2\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle 3\) | |||
| x | |||||||
| \(\displaystyle \bf2\) | \(\displaystyle 1\) | \(\displaystyle 2\) | |||||
| \(\displaystyle 4\) | \(\displaystyle 4\) | \(\displaystyle 2\) | \(\displaystyle 4\) | \(\displaystyle 6\) | |||
| \(\displaystyle +\) | |||||||
| \(\displaystyle 2\) | \(\displaystyle 2\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle 3\) | |||
| \(\displaystyle +\) | |||||||
| \(\displaystyle \bf4\) | \(\displaystyle \bf4\) | \(\displaystyle \bf2\) | \(\displaystyle \bf4\) | \(\displaystyle \bf6\) | |||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |
4. Четвертое действие.
Складываем получившиеся числа:
| \(\displaystyle 4\) | \(\displaystyle 4\) | \(\displaystyle 2\) | \(\displaystyle 4\) | \(\displaystyle 6\) | |||
| \(\displaystyle +\) | |||||||
| \(\displaystyle 2\) | \(\displaystyle 2\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle 3\) | |||
| \(\displaystyle +\) | |||||||
| \(\displaystyle 4\) | \(\displaystyle 4\) | \(\displaystyle 2\) | \(\displaystyle 4\) | \(\displaystyle 6\) | |||
| \(\displaystyle 4\) | \(\displaystyle 6\) | \(\displaystyle 9\) | \(\displaystyle 0\) | \(\displaystyle 0\) | \(\displaystyle 7\) | \(\displaystyle 6\) | |
В итоге имеем:
| \(\displaystyle 2\) | \(\displaystyle 2\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle 3\) | |||
| x | |||||||
| \(\displaystyle 2\) | \(\displaystyle 1\) | \(\displaystyle 2\) | |||||
| \(\displaystyle 4\) | \(\displaystyle 4\) | \(\displaystyle 2\) | \(\displaystyle 4\) | \(\displaystyle 6\) | |||
| \(\displaystyle +\) | |||||||
| \(\displaystyle 2\) | \(\displaystyle 2\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle 3\) | |||
| \(\displaystyle +\) | |||||||
| \(\displaystyle 4\) | \(\displaystyle 4\) | \(\displaystyle 2\) | \(\displaystyle 4\) | \(\displaystyle 6\) | |||
| \(\displaystyle \bf4\) | \(\displaystyle \bf6\) | \(\displaystyle \bf9\) | \(\displaystyle \bf0\) | \(\displaystyle \bf0\) | \(\displaystyle \bf7\) | \(\displaystyle \bf6\) | |
Ответ: \(\displaystyle 4690076{\small.}\)