# Theory: Значения синуса, косинуса и формулы приведения

Заполните таблицу:

 $$\displaystyle \frac{2\pi}{3}$$ $$\displaystyle \frac{3\pi}{4}$$ $$\displaystyle \frac{5\pi}{6}$$ $$\displaystyle \frac{7\pi}{6}$$ $$\displaystyle \frac{5\pi}{4}$$ $$\displaystyle \frac{4\pi}{3}$$ $$\displaystyle \sin$$ $$\displaystyle \frac{\sqrt{3}}{2}$$ $$\displaystyle \frac{\sqrt{2}}{2}$$ $$\displaystyle \frac{1}{2}$$ $$\displaystyle -\frac{1}{2}$$ $$\displaystyle -\frac{\sqrt{2}}{2}$$ $$\displaystyle -\frac{\sqrt{3}}{2}$$ $$\displaystyle \cos$$ $$\displaystyle -\frac{1}{2}$$ $$\displaystyle -\frac{\sqrt{2}}{2}$$ $$\displaystyle -\frac{\sqrt{3}}{2}$$ $$\displaystyle -\frac{\sqrt{3}}{2}$$ $$\displaystyle -\frac{\sqrt{2}}{2}$$ $$\displaystyle -\frac{1}{2}$$

 $$\displaystyle \frac{5\pi}{3}$$ $$\displaystyle \frac{7\pi}{3}$$ $$\displaystyle \frac{11\pi}{3}$$ $$\displaystyle \sin$$ $$\displaystyle -\frac{\sqrt{3}}{2}$$ $$\displaystyle \frac{\sqrt{3}}{2}$$ $$\displaystyle -\frac{\sqrt{3}}{2}$$ $$\displaystyle \cos$$ $$\displaystyle \frac{1}{2}$$ $$\displaystyle \frac{1}{2}$$ $$\displaystyle \frac{1}{2}$$
Solution

$$\displaystyle \sin\frac{5\pi}{6}=\frac{1}{2}$$

$$\displaystyle \sin\frac{7\pi}{6}=-\frac{1}{2}$$

$$\displaystyle \cos\frac{5\pi}{6}=-\frac{\sqrt{3}}{2}$$

$$\displaystyle \cos\frac{7\pi}{6}=-\frac{\sqrt{3}}{2}$$

$$\displaystyle \sin\frac{2\pi}{3}=\frac{\sqrt{3}}{2}.$$

$$\displaystyle \sin\frac{4\pi}{3}=-\frac{\sqrt{3}}{2}.$$

$$\displaystyle \cos\frac{4\pi}{3}=-\frac{1}{2}$$

$$\displaystyle \sin(\frac{3\pi}{4})=\frac{\sqrt{2}}{2}$$

$$\displaystyle \cos\frac{3\pi}{4}=-\frac{\sqrt{2}}{2}$$

$$\displaystyle \sin\frac{5\pi}{4}=-\frac{\sqrt{2}}{2}$$

$$\displaystyle \cos\frac{5\pi}{4}=-\frac{\sqrt{2}}{2}$$

$$\displaystyle \sin\frac{7\pi}{4}=-\frac{\sqrt{2}}{2}$$

$$\displaystyle \cos\frac{7\pi}{4}=\frac{\sqrt{2}}{2}$$

$$\displaystyle \sin\frac{5\pi}{3}=-\frac{\sqrt{3}}{2}$$

$$\displaystyle \cos\frac{5\pi}{3}=\frac{1}{2}$$

$$\displaystyle \sin\frac{11\pi}{6}=-\frac{1}{2}$$

$$\displaystyle \cos\frac{11\pi}{6}=\frac{\sqrt{3}}{2}$$

$$\displaystyle \sin\frac{11\pi}{3}=-\frac{\sqrt{3}}{2}.$$

$$\displaystyle \cos \frac{11\pi}{3}=\frac{1}{2}.$$