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Теория: Умножение двузначных чисел

Задание

Перемножить числа:

  \(\displaystyle \times\) \(\displaystyle 2\) \(\displaystyle 3\)
  \(\displaystyle 3\) \(\displaystyle 2\)
\(\displaystyle +\)  
 
 

 

Решение

1. Умножаем единицы числа \(\displaystyle 3\underline{2} \) (это цифра \(\displaystyle 2 \)) на число \(\displaystyle 23 {\small : }\)

 

\(\displaystyle 2 \cdot 23=46 {\small . }\)

 

  \(\displaystyle \times\) \(\displaystyle \bf2\) \(\displaystyle \bf3\)
  \(\displaystyle 3\) \(\displaystyle \bf2\)
\(\displaystyle +\)   \(\displaystyle \bf4\) \(\displaystyle \bf6\)
  \(\displaystyle ?\) \(\displaystyle ?\)  
  \(\displaystyle ?\) \(\displaystyle ?\) \(\displaystyle ?\)

 

2. Умножаем десятки числа \(\displaystyle \underline{3}2 \) (это цифра \(\displaystyle 3 \)) на число \(\displaystyle 23 {\small : }\)

 

\(\displaystyle 3 \cdot 23=69 {\small . } \)

 

  \(\displaystyle \times\) \(\displaystyle \bf2\) \(\displaystyle \bf3\)
  \(\displaystyle \bf3\) \(\displaystyle 2\)
\(\displaystyle +\)   \(\displaystyle 4\) \(\displaystyle 6\)
\(\displaystyle \bf6\) \(\displaystyle \bf9\)  
  \(\displaystyle ?\) \(\displaystyle ?\) \(\displaystyle ?\)

 

3. Складываем числа:

\(\displaystyle +\)   \(\displaystyle 4\) \(\displaystyle 6\)
  \(\displaystyle 6\) \(\displaystyle 9\)  
  \(\displaystyle 7\) \(\displaystyle 3\) \(\displaystyle 6\)

 

В итоге мы получаем:

  \(\displaystyle \times\) \(\displaystyle 2\) \(\displaystyle 3\)
  \(\displaystyle 3\) \(\displaystyle 2\)
\(\displaystyle +\)   \(\displaystyle 4\) \(\displaystyle 6\)
  \(\displaystyle 6\) \(\displaystyle 9\)  
  \(\displaystyle 7\) \(\displaystyle 3\) \(\displaystyle 6\)

Ответ: \(\displaystyle 736 {\small . }\)