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Теория: Умножение двузначных чисел

Задание

Перемножить числа:

    \(\displaystyle \times\) \(\displaystyle 7\) \(\displaystyle 2\)
  \(\displaystyle 3\) \(\displaystyle 6\)
\(\displaystyle +\)  
 
 

 

Решение

1. Умножаем единицы числа \(\displaystyle 3\underline{6} \) (это цифра \(\displaystyle 6\)) на число \(\displaystyle 72{\small : }\)

 

\(\displaystyle 6\cdot 72=432{\small . }\)

 

    \(\displaystyle \times\) \(\displaystyle \bf 7\) \(\displaystyle \bf 2\)
  \(\displaystyle 3\) \(\displaystyle \bf 6\)
\(\displaystyle +\)   \(\displaystyle \bf 4\) \(\displaystyle \bf 3\) \(\displaystyle \bf 2\)
\(\displaystyle ?\) \(\displaystyle ?\) \(\displaystyle ?\)  
  \(\displaystyle ?\) \(\displaystyle ?\) \(\displaystyle ?\) \(\displaystyle ?\)

 

2. Умножаем десятки числа \(\displaystyle \underline{3}6\) (это цифра \(\displaystyle 3\)) на число \(\displaystyle 72{\small : }\)

 

\(\displaystyle 3\cdot 72=216{\small . }\)

 

    \(\displaystyle \times\) \(\displaystyle \bf 7\) \(\displaystyle \bf 2\)
  \(\displaystyle \bf 3\) \(\displaystyle 6\)
\(\displaystyle +\)   \(\displaystyle 4\) \(\displaystyle 3\) \(\displaystyle 2\)
\(\displaystyle \bf 2\) \(\displaystyle \bf 1\) \(\displaystyle \bf 6\)  
  \(\displaystyle ?\) \(\displaystyle ?\) \(\displaystyle ?\) \(\displaystyle ?\)

 

3. Складываем числа:

\(\displaystyle +\)   \(\displaystyle 4\) \(\displaystyle 3\) \(\displaystyle 2\)
\(\displaystyle 2\) \(\displaystyle 1\) \(\displaystyle 6\)    
  \(\displaystyle 2\) \(\displaystyle 5\) \(\displaystyle 9\) \(\displaystyle 2\)

 

В итоге мы получаем:

    \(\displaystyle \times\) \(\displaystyle 7\) \(\displaystyle 2\)
  \(\displaystyle 3\) \(\displaystyle 6\)
\(\displaystyle +\)   \(\displaystyle 4\) \(\displaystyle 3\) \(\displaystyle 2\)
\(\displaystyle 2\) \(\displaystyle 1\) \(\displaystyle 6\)  
  \(\displaystyle 2\) \(\displaystyle 5\) \(\displaystyle 9\) \(\displaystyle 2\)

Ответ: \(\displaystyle 2592{\small . }\)